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What is the chemical structure of 5-methyl-2- [4-methyl-5-oxo-4- (propan-2-yl) -4, 5-dihydro-1H-imidazol-2-yl] pyridine-3-carboxylic acid
Alas! This is the name of an organic compound. To clarify its chemical structure, we need to analyze this name in detail. "5 - methyl - 2 - [4 - methyl - 5 - oxo - 4 - (propan - 2 - yl) -4,5 - dihydro - 1H - imidazol - 2 - yl] pyridine - 3 - carboxylic acid", from the name, the main structure is pyridine (pyridine). There is methyl at the 5th position of pyridine, and a complex group at the 2nd position. In this complex group, the core is an imidazole derivative, with propan-2-yl at the 4th position, oxo at the 5th position, and double bonds between the 4th and 5th positions, forming a 4,5-dihydro-1H-imidazole structure. At the same time, the 3rd position of pyridine is connected with a carboxylic acid.
Looking at the naming of this compound, it can be seen that its structure is complex and each substituent is arranged in an orderly manner. From the perspective of chemical structure, the pyridine ring is the basic framework, and each substituent occupies a specific position according to the naming rules, which together build the unique structure of this organic compound. This structure may endow the compound with specific chemical properties and reactivity, and may have potential uses in organic synthesis, medicinal chemistry, and other fields.
What are the physical properties of 5-methyl-2- [4-methyl-5-oxo-4- (propan-2-yl) -4, 5-dihydro-1H-imidazol-2-yl] pyridine-3-carboxylic acid
5-Methyl-2- [4-methyl-5-oxo-4- (propyl-2-yl) -4,5-dihydro-1H-imidazole-2-yl] pyridine-3-carboxylic acid, which is an organic compound. Looking at its molecular structure, it contains imidazole ring and pyridine ring, and is connected with methyl, isopropyl and carboxyl groups.
In terms of its physical properties, it may be solid under normal conditions, because many organic compounds with similar structures are solid. In terms of melting point, due to the interaction of hydrogen bonds and van der Waals forces in the molecule, the intermolecular binding is close, and the melting point may be relatively high. However, the specific value needs to be determined accurately by experiment, and the electronic effect and spatial effect of the surrounding group will have a significant impact on it.
In terms of solubility, given that it contains a hydrophilic group of carboxyl groups, it may have a certain solubility in polar solvents (such as water and alcohols). However, the molecule contains more hydrophobic alkyl groups, so the solubility in non-polar solvents (such as alkanes) may be poor.
In addition, the compound may have certain stability, because the imidazole ring and the pyridine ring conjugate system can provide electron delocalization and enhance molecular stability. However, under extreme conditions such as strong acids, strong bases, or high temperatures, some chemical bonds in the molecules may break, causing structural changes.
What is the main use of 5-methyl-2- [4-methyl-5-oxo-4- (propan-2-yl) -4, 5-dihydro-1H-imidazol-2-yl] pyridine-3-carboxylic acid
5-Methyl-2- [4-methyl-5-oxo-4- (propylene-2-yl) -4,5-dihydro-1H-imidazole-2-yl] pyridine-3-carboxylic acid is very useful in today's pharmaceutical and chemical fields.
In the pharmaceutical field, it may be a key intermediate for drug development. Due to its unique chemical structure, it can interact with specific biological macromolecules in the body, such as proteins, nucleic acids, etc. Based on this, through subtle chemical modification and optimization, new drugs can be created for the treatment of various diseases. For example, for specific enzymes or receptors, drugs designed with this substance as the starting material may be expected to intervene in related biological signaling pathways for the treatment of cancer, inflammation, cardiovascular diseases and other purposes.
In the chemical industry, it can be used as an important building block for organic synthesis. Because it contains a variety of active functional groups, it can participate in many chemical reactions, such as esterification, amidation, cyclization, etc. With these reactions, more complex and diverse organic compounds can be constructed for the preparation of high-performance materials, such as polymer materials with special optical, electrical or mechanical properties, and then applied in the fields of electronics, optics and materials science to meet the needs of different industries for special performance materials.
What are the synthesis methods of 5-methyl-2- [4-methyl-5-oxo-4- (propan-2-yl) -4, 5-dihydro-1H-imidazol-2-yl] pyridine-3-carboxylic acid
The synthesis method of 5-methyl-2-[ 4-methyl-5-oxo-4- (propane-2-yl) -4,5-dihydro-1H-imidazole-2-yl] pyridine-3-carboxylic acid involves the technique of organic synthesis. The method is as follows:
First, a suitable pyridine derivative is used as the starting material. At a specific position of this derivative, a halogenation reaction is carried out to introduce a halogen atom. For example, with a halogenated reagent, under appropriate reaction conditions, the corresponding check point on the pyridine ring is halogenated. This halogenation reaction condition needs to be precisely controlled, such as the reaction temperature, reaction time and the ratio of reagent dosage, which will affect the yield and purity of the halogenated product.
Then, a compound containing an imidazole structure, which should have a specific substituent, is coupled to the above-mentioned halogenated pyridine derivative. This reaction often requires the help of catalysts, such as palladium-based catalysts. In an alkaline environment, the coupling of the two is promoted by a specific reaction time and temperature to form the basic skeleton of the target product. During the reaction, the choice of solvent is also critical, and different solvents affect the reaction rate and selectivity.
Furthermore, for the intermediate obtained in the reaction, the carboxylation reaction is carried out. A suitable carboxylation reagent can be selected to introduce carboxyl groups at designated positions in the pyridine ring under specific reaction conditions. In this step, the optimization of reaction conditions is extremely important, including the pH of the reaction system, temperature changes, etc., to ensure that the carboxylation reaction is carried out efficiently and accurately.
Or another synthesis path can be established, the imidazole structure is first constructed, and then it is connected to the pyridine derivative. With suitable raw materials, the imidazole compound containing specific substituents is synthesized through multi-step reaction, and then reacted with the pyridine derivative under appropriate conditions, and then modified by subsequent reactions, such as methylation, to achieve the synthesis of the target product. Each step of the reaction requires the separation and purification of the intermediate. Column chromatography, recrystallization and other means are often used to ensure the purity of the product and facilitate the successful synthesis of the final target product.
What is the price of 5-methyl-2- [4-methyl-5-oxo-4- (propan-2-yl) -4, 5-dihydro-1H-imidazol-2-yl] pyridine-3-carboxylic acid in the market?
What you are inquiring about is the price of "5 - methyl - 2 - [4 - methyl - 5 - oxo - 4 - (propan - 2 - yl) -4,5 - dihydro - 1H - imidazol - 2 - yl] pyridine - 3 - carboxylic acid" in the market. However, this product is not a well-known common thing, and its price is difficult to determine.
The price of this product is often affected by many factors. First, the ease of synthesis of this product has a great impact. If the synthesis process is complicated, many fine steps are required, or special raw materials and equipment are required, the cost will be high, and the price will also rise. Second, the amount of market demand is also the key. If there is a strong demand for this product in the fields of pharmaceutical research and development, chemical production, etc., and the supply is limited, the price will tend to be higher; conversely, if there is a lack of demand and sufficient supply, the price may be lower. Third, differences in manufacturers also play a role. Different manufacturers may set different prices due to factors such as technical level and production cost control.
To determine the exact price of this product, you may need to consult a professional chemical product trading platform, consult a professional chemical raw material supplier, or inquire at relevant academic and industrial exchanges to obtain a more accurate price.