2 4 5 Dihydro 4 Methyl 4 1 Methylethyl 5 Oxo 1h Imidazol 2 Yl 3 Pyridine
pyridine pyrrole pyrazine piperidine piperazine

2-(4,5-dihydro-4-methyl-4-(1-methylethyl)-5-oxo-1h-imidazol-2-yl)-3-pyridine

    Specifications

    HS Code

    947686

    Chemical Formula C13H17N3O2
    Molar Mass 247.294 g/mol
    Solubility In Water Low solubility expected due to its non - polar groups
    Solubility In Organic Solvents Soluble in common organic solvents like dichloromethane, chloroform
    Stability Stable under normal conditions, but may react with strong oxidizing or reducing agents

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    Frequently Asked Questions

    As a leading 2-(4,5-dihydro-4-methyl-4-(1-methylethyl)-5-oxo-1h-imidazol-2-yl)-3-pyridine supplier, we deliver high-quality products across diverse grades to meet evolving needs, empowering global customers with safe, efficient, and compliant chemical solutions.

    What is the chemical structure of 2- (4,5-dihydro-4-methyl-4- (1-methylethyl) -5-oxo-1H-imidazole-2-yl) -3-pyridine?
    The naming of this organic compound can be deduced according to its rules. The name "2 - (4,5 - dioxo - 4 - methyl - 4 - (1 - methylethyl) - 5 - oxo - 1H - pyrrole - 2 - yl) - 3 - pyridine".
    First look at "2 - (...) - 3 - pyridine", it can be seen that this compound uses pyridine as the parent nucleus and has substituents at the 2nd and 3rd positions of the pyridine ring, respectively.
    Further analysis of the structure in parentheses, "4,5-dioxy", shows that there is an oxygen atom connected to the 4th and 5th positions of a certain structure; "4-methyl", that is, the 4th position is connected with methyl; "4- (1-methylethyl) ", this 1-methylethyl group is isopropyl, which is connected to the 4th position; "5-oxo", which means that the 5th position has a carbonyl group; "1H-pyrrole-2-yl", indicating that this is a pyrrole ring, and the second position of the pyrrole ring is connected to the pyridine ring.
    In synthesis, this compound has a pyridine ring as the core, and a complex substituent is connected at the 2-position. This substituent contains a pyrrole ring. The 4-position of the pyrrole ring has methyl and isopropyl, the 4-position and 5-position each have an oxygen atom, and the 5-position is a carbonyl group. In this way, the chemical structure of this compound can be obtained.
    What are the physical properties of 2- (4,5-dihydro-4-methyl-4- (1-methylethyl) -5-oxo-1H-imidazole-2-yl) -3-pyridine?
    This is the product of 2- (4,5-dioxy-4-methyl-4- (1-methylethyl) -5-oxo-1H-pyrrole-2-yl) -3-pyridine. This substance has a number of physical properties.
    Looking at its properties, under normal temperature and pressure, it is either solid, mostly powdery, or nearly white in color, or in a white-like state. Fine observation shows that the texture of the powder is uniform, due to intermolecular forces and crystal structure.
    When it comes to the melting boiling point, due to the fact that there are many polar groups and complex structures in the molecule, the intermolecular force is strong, so the melting point is quite high, about [X] ° C, and a considerable amount of heat is required to break the attractive force between molecules, so that it melts into a liquid state; the boiling point is not low, about [X] ° C, because in order to make it vaporized, more energy is required to overcome the intermolecular force.
    In terms of solubility, its solubility in water is poor, and it is difficult to interact effectively with water molecules due to the non-high polarity of the molecule as a whole; however, in organic solvents such as ethanol and dichloromethane, the solubility is relatively high, because organic solvents and the molecules of the substance can interact with van der Waals force and hydrogen bonds to promote their dissolution. < Br >
    In terms of density, the density of this substance is slightly larger than that of water, about [X] g/cm ³, which is determined by the molecular mass and the degree of molecular accumulation. In common organic solvents, it will sink to the bottom.
    The physical properties of this substance are all derived from its unique molecular structure. The interaction of various groups jointly casts the above physical properties. These properties are of key guiding significance in chemical synthesis, drug development and other fields.
    What are the main uses of 2- (4,5-dihydro-4-methyl-4- (1-methylethyl) -5-oxo-1H-imidazole-2-yl) -3-pyridine?
    This is 2- (4,5-dioxy-4-methyl-4- (1-methylethyl) -5-oxo-1H-pyrrole-2-yl) -3-pyridine. The main uses of this substance are quite extensive.
    In the field of medicine, it may have unique pharmacological activities and can be used as a lead compound for the development of new drugs. Due to its special chemical structure, it may interact with specific biological targets, regulate physiological processes, and have potential value in the treatment of diseases such as inflammation and tumors. For example, it has been found that some compounds containing similar structures can effectively inhibit the proliferation of tumor cells, so it is speculated that this compound may also be further researched and developed in the direction of anti-tumor drugs.
    In the field of materials science, its structural properties may endow materials with unique physical and chemical properties. For example, in organic optoelectronic materials, its conjugate structure and other characteristics can be used to improve the optical properties of materials, such as improving the fluorescence efficiency and charge transport capacity of materials, so as to be used in the manufacture of high-performance Light Emitting Diodes, solar cells and other optoelectronic devices.
    In the field of pesticides, it may show good biological activity. It can be targeted at specific pests or pathogens, and by virtue of its chemical structure and the relevant action of the organism, it can achieve the purpose of efficient prevention and control of pests and diseases, and provide new and efficient pesticide products for agricultural production.
    What are the synthesis methods of 2- (4,5-dihydro-4-methyl-4- (1-methylethyl) -5-oxo-1H-imidazole-2-yl) -3-pyridine?
    To prepare 2 - (4,5 - dihydro - 4 - methyl - 4 - (1 - methylethyl) - 5 - oxo - 1H - pyrazole - 2 - yl) - 3 - pyridine, there are many synthesis methods, several common methods are described in detail below.
    ** Method 1: Take a specific pyridine derivative as the starting material **
    and combine it with a reagent containing 4,5-dihydro-4-methyl-4- (1-methylethyl) -5-oxo-1H-pyrazole-2-based structure. In the presence of suitable bases and catalysts, nucleophilic substitution reactions are carried out in organic solvents. For example, potassium carbonate is used as a base, cuprous iodide is used as a catalyst, and the reaction is heated and stirred in N, N-dimethylformamide (DMF) solvent for several hours. After the reaction is completed, the target product can be obtained by conventional separation methods such as extraction and column chromatography. The starting materials of this route are easy to obtain, and the reaction conditions are relatively mild. However, the reaction steps may be complicated, and the reaction conditions need to be carefully controlled to improve the yield and purity.
    ** Method 2: Construct **
    via pyrazole derivatives. First, 4,5-dihydro-4-methyl-4- (1-methylethyl) -5-oxo-1H-pyrazole-2-yl related intermediates are prepared, and then linked to the pyridine structure fragment. If ethyl acetoacetate is used as the starting material, a pyrazole ring is constructed through a series of reactions, and then coupled with pyridine derivatives under suitable conditions. Triethylamine can be selected as a base, and the reaction is catalyzed by palladium catalyst in dichloromethane solvent. After the reaction is completed, the product is purified by washing, drying, distillation and other operations. This method has higher requirements for the construction of pyrazole rings, but it can better control the structure of the target product, and the yield may be considerable.
    ** Method 3: Using the cyclization reaction strategy **
    to select the linear precursor compound containing the structural fragments of pyridine and pyrazole, and synthesize the target product through the intramolecular cyclization reaction. Using a suitable acid or base as a catalyst to promote cyclization under high temperature or microwave radiation conditions. For example, p-toluenesulfonic acid is used as a catalyst for reflux reaction in toluene solvent. This method has short steps and high atomic economy. However, the synthesis of precursor compounds may be challenging, and the cyclization reaction conditions need to be optimized to avoid side reactions.
    What are the market prospects for 2- (4,5-dihydro-4-methyl-4- (1-methylethyl) -5-oxo-1H-imidazole-2-yl) -3-pyridine?
    Today, there are 2- (4,5-dioxo-4-methyl-4- (1-methylethyl) -5-oxo-1H-pyrrole-2-yl) -3-. What is the market prospect for it?
    I look at this thing, its structure is unique, and its characteristics may attract attention in general fields. In the pharmaceutical industry, its special molecular structure may become an opportunity to develop new drugs. The specific group in this structure may have an affinity for certain disease targets. With time, in-depth exploration may lead to the development of new therapeutic drugs and the well-being of patients. The market potential cannot be underestimated.
    In the field of materials, it also has potential. The chemical properties contained in the compound may endow the material with novel properties. For example, if it is integrated into polymer materials, it may improve the stability and flexibility of the material, and then open up new application scenarios, such as high-end packaging materials, plastic products with special functions, etc., it is also expected to gain a place in this field.
    However, its market prospects are not smooth. The cost of research and development may be a major challenge. The synthesis of this complex compound requires a lot of raw materials, technology and manpower. And the market competition is fierce, and similar or alternative products also exist. If you want to emerge in the market, you need to speed up the research and development process, improve production efficiency, reduce costs, and increase publicity efforts to make all walks of life aware of its unique advantages in order to take the lead in the market. Although the future is bright, you still need to make unremitting progress.